Active Reading Solution: Relativity and Bubble Chambers
- Δt = Δx/v = 3.3×10-15 s
- Δt / γ = 3.3×10-17 s
- We have seen that a particle with a lifetime of 3.3×10-17 s (as measured in its own reference frame, which is of course the correct frame for determining when it will decay) would leave a track of 10-6 m, which is the shortest track we can currently measure. So any longer lifetime will leave a longer track, and therefore be more easily detectable.